Transformation Of Graph Dse Exercise 【Validated ★】

The transformation of graphs in the Hong Kong Diploma of Secondary Education (HKDSE) curriculum involves modifying the function

Method 1 (Algebraic Substitution): $y = [(x + 3)^2 - 4(x + 3)] - 5$ $y = [x^2 + 6x + 9 - 4x - 12] - 5$ $y = x^2 + 2x + 2 - 5$ Answer: $y = x^2 + 2x - 3$ transformation of graph dse exercise

| Year | Paper | Question | Focus | |------|-------|----------|-------| | 2023 | 1 (Core) | Q.12 | Composite transformations (quadratic to cubic) | | 2022 | 2 (MCQ) | Q.28 | Horizontal vs vertical scaling in exponential graphs | | 2021 | M2 | Q.6b | Transformations and inflection points | | 2019 | 1 | Q.9 | Absolute value and translation | | 2018 | 2 | Q.33 | Sine graph: find amplitude, period, phase shift | The transformation of graphs in the Hong Kong

A transformation of a graph exercise in the DSE (Diploma of Secondary Education) typically focuses on how specific changes to an algebraic function— intercepts at ( x = -1

Domain of (\sqrt-x/3): (-x/3 \ge 0 \implies x \le 0)
Range: (\sqrt\dots \ge 0 \implies \sqrt\dots + 2 \ge 2)

Solution

( f(x) = (x-1)^2 - 4 ) has vertex ( (1,-4) ), intercepts at ( x = -1, 3 ).