Tippens 7 Edicion Solucionario — Paul E
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Parte II: Movimiento Rotacional y Gravitación
Capítulo 9: Movimiento Circular Uniforme μ = 0.4
- Vectors and projectiles
- Uniform circular motion
- Relative motion
- Electric charges and fields
- Electric potential
- Capacitance and dielectrics
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Solucionario Excerpt: Datos: m = 10 kg, μ = 0.4, a = 2 m/s², g = 9.8 m/s². Fórmulas: F_net = m·a ; F_friction = μ·N ; N = m·g. Desarrollo: F_applied - μ·m·g = m·a → F_applied = m·a + μ·m·g = 10(2) + 0.4(10)(9.8) = 20 + 39.2 = 59.2 N. Respuesta: 59.2 N