9.1.6 Checkerboard V1 Codehs |work| Site

Investigation: "9.1.6 checkerboard v1 codehs"

Summary

This document analyzes the problem titled "9.1.6 checkerboard v1" from CodeHS (assumed exercise naming), reconstructs likely requirements, explains correct algorithmic approaches, provides a rigorous step‑by‑step solution, proves correctness, highlights edge cases, and offers an annotated reference implementation in Python (readable pseudocode for educators/students). Assumptions about the exact original prompt are made explicit where the source problem text is unavailable.

Create the 8x8 checkerboard

for i in range(8): row = [] for j in range(8): if (i + j) % 2 == 0: row.append("R") # R for red else: row.append("B") # B for black board.append(row) 9.1.6 checkerboard v1 codehs

A checkerboard pattern relies on the parity of the coordinates. You can visualize the index sums like this: ✅ Final Result The program successfully generates an grid where every adjacent cell alternates between , starting with at position [0][0]. Investigation: "9

• 1x1: Just one beeper.
• 2x2: Beeper at (1,1), empty at (1,2); empty at (2,1), beeper at (2,2).
• 3x3: B . B / . B . / B . B
• 5x8: Alternates correctly across even/odd width.